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Euler Graphs
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The explorer's Problem: An explorer wants to explore all the routes between a number of cities. Can a tour be found which traverses each route only once? Particularly, find a tour which starts at A, goes along each road exactly once, and ends back at A.
Examples of such tour are
A | B | C | D | E | F | B | G | C | E | G | F | A | ||
A | F | G | C | D | E | G | B | C | E | F | B | A |
The Explorer travels along each road (edges) just once but may visit a particular city (vertex) several times.
The Traveler's Problem
A traveler wants to visit a number of cities. Can a tour be found which visits each city only once? Particularly, find a tour which starts at A, goes to each city exactly once, and ends back at A.
Examples of such tour are
A | B | C | D | E | G | F | A | ||
A | F | E | D | C | G | B | A |
The travelers visits each city (vertex) just once but may omit several of the roads (edges) on the way.
Eulerian Trail
A connected graph G is Eulerian if there is a closed trail which includes every edge of G, such a trail is called an Eulerian trail.
Hamiltonian Cycle
A connected graph G is Hamiltonian if there is a cycle which includes every vertex of G; such a cycle is called a Hamiltonian cycle.
Consider the following examples:
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This graph is BOTH Eulerian and Hamiltonian.
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This graph is Eulerian, but NOT Hamiltonian.
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This graph is an Hamiltionian, but NOT Eulerian.
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This graph is NEITHER Eulerian NOR Hamiltionian
Theorem Let G be a connected graph. Then G is Eulerian if and only if every vertex of G has even degree.
- Necessary Condition
- If G is Eulerian, then every vertex of G has even degree.
- Sufficient Condition
- If every vertex of G has even degree, then G is Eulerian.
Eulerian-Type Problems
- Edge-traceable graphs.
- Diagrams-Tracing Puzzles.
- Dominoes.
- Mazes and labyrinths,
- The Chinese Postman Problem.
- The Rotating Drum Problem.
Sufficient Condition
Dirac's Theorem Let G be a simple graph with n vertices where n ≥ 3 If deg(v) ≥ 1/2 n for each vertex v, then G is Hamiltonian.
For example,
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n = 6 and deg(v) = 3 for each vertex, so this graph is Hamiltonian by Dirac's theorem.
Ore's Theorem Let G be a simple graph with n vertices where n ≥ 2 if deg(v) + deg(w) ≥ n for each pair of non-adjacent vertices v and w, then G is Hamiltonian.
For example,
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n = 5 but deg(u) = 2, so Dirac's theorem does not apply. However, deg(v) + deg(w) ≥ 5 for all pairs of vertices v and w (infact, for all pairs of vertices v and w), so this graph is Hamiltonian by Ore's theorem.
Note that if deg(v) ≥ 1/2 n for each vertex, then deg(v) + deg(w) ≥ n for each pair of vertices v and w. It follows that Dirac's theorem can be deduced from Ore's theorem, so we prove only Ore's threoem.
Hamiltonain - Type Problem
- Gray Codes.
- The Traveling Salesperson Problem
- Ranking in Tournaments.
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